If the energy difference between two electronic sates is 214.68Kj/mol, calculate the frequency of light emitted when an electron drops from the higher to lower states.
?E = hv or v = ?E
E = 214.68 kJ mol-1, h = 39.79 x 10-14 kJ mol-1
v = 214.68
v = 214.68 X 1014
= 5.39 x 1014 s-1