Question
Sun March 15, 2015 By: Godson Babuji

Find the probability that a leap year & a non leap year selected at random has :
 
  1) 52 sundays 
  
  2) 53 sundays
 
  pls explain me clearly !

Expert Reply
Prasenjit Paul
Sun March 15, 2015
N u m b e r space o f space d a y s space i n space a space n o n minus l e a p space y e a r space equals 365 equals 52 space w e e k s space a n d space 1 space e x t r a space d a y N u m b e r space o f space d a y s space i n space a space l e a p space y e a r space equals 366 equals 52 space w e e k s space a n d space 2 space e x t r a space d a y s.  1 right parenthesis space 52 space s u n d a y s comma I n space c a s e space o f space a space n o n minus l e a p space y e a r comma space 1 space e x t r a space d a y space s h o u l d space n o t space b e space a space s u n d a y P left parenthesis n o n minus l e a p space y e a r space h a s space 52 space s u n d a y s right parenthesis equals 1 minus 1 over 7 equals 6 over 7 I n space c a s e space o f space a space l e a p space y e a r comma space o n e space o f space t h e space 2 space e x t r a space d a y s space s h o u l d space n o t space b e space a space s u n d a y P left parenthesis l e a p space y e a r space h a s space 52 space s u n d a y s right parenthesis equals 1 minus 1 over 7 equals 6 over 7  2 right parenthesis space 53 space s u n d a y s comma I n space c a s e space o f space a space n o n minus l e a p space y e a r comma space 1 space e x t r a space d a y space s h o u l d space b e space a space s u n d a y P left parenthesis n o n minus l e a p space y e a r space h a s space 53 space s u n d a y s right parenthesis equals 1 over 7 I n space c a s e space o f space a space l e a p space y e a r comma space o n e space o f space t h e space 2 space e x t r a space d a y s space s h o u l d space space b e space a space s u n d a y P left parenthesis l e a p space y e a r space h a s space 53 space s u n d a y s right parenthesis equals 1 over 7
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