Thu June 30, 2011 By: Gaurav Nagpal

Equal and similar charges are placed on the earth and the moon. The value of charge required to neutralize their gravitational attraction is

Expert Reply
Fri July 01, 2011
According to the given condition is that 
Coulombic repulsion = Gravitational attraction
(1/4??0)(q2/r2) = G m2/r2
   q = sqrt (G m2 / 9 x 109)
So the value of charge can be calculated by substituting the values of G and mass of the charge.
Sat September 02, 2017


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