A.P. plzzzz hurry
The extra subscript 1 and 2 refers to the first and second AP respectively.
For example, (Sn)1 = sum of n terms for 1st AP, and so on.
(Sn)1/(Sn)2 = (7n+1)/(4n+27) = (2a1+(n-1)d1)/(2a2+(n-1)d2)
Taking n = 9,
64/63 = (2a1+8d1)/(2a2+8d2) = (a1+4d1)/(a2+4d2)
(a5)1 = a1+4d1
(a5)2 = a2+4d2
(a5)1/(a5)2 = (a1+4d1)/(a2+4d2) = 64/63
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