Question
Mon August 31, 2009 By: Suchet Raghavan

algebra

Expert Reply
Mon August 31, 2009

Let the number of pottery articles in a day be n, and cost of production of each be p rupees.

2n +3 = p

np = 90

p = 90/n

2n + 3 = 90/n

2n2 + 3n - 90 = 0

n = [-3 ±(9 - (4)(2)(-90))]/4

n = [-3 ±(729)]/4

n = [-3 +27]/4 

n = 6 and p = 90/6 = 15.

Number of articles produced = 6,

Cost of each article = 15.

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