A cottage industry produces a certain number of pottery articles in a day. It was observed
on a particular day that the cost of production of each article (in rupees) was 3 more than
twice the number of articles produced on that day. If t
Let the number of pottery articles in a day be n, and cost of production of each be p rupees.
2n +3 = p
np = 90
p = 90/n
2n + 3 = 90/n
2n2 + 3n - 90 = 0
n = [-3 ±(9 - (4)(2)(-90))]/4
n = [-3 ±(729)]/4
n = [-3 +27]/4
n = 6 and p = 90/6 = 15.
Number of articles produced = 6,
Cost of each article = 15.
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