A car, starting from rest, accelerates at a rate 'f' through a distance 's', then continues at a constant speed for sometime 't' and then decelerates at the rate 'f/2' to come to rest. If the total distance is '5s', then prove that s=1/2ft^2 or s=1/2f(t)square
Initial speed =0
Thus using the third equation of motion we can find the final velocity after moving a distance s.
After that the car moved at a constant speed for t time we can calculate the distance travelled:
Now after that it is decelerated by f/2 so we can find the distance covered as:
Now total distance travelled is 5s