Tue June 19, 2012 By: Ratik Mahajan

A car, starting from rest, accelerates at a rate 'f' through a distance 's', then continues at a constant speed for sometime 't' and then decelerates at the rate 'f/2' to come to rest. If the total distance is '5s', then prove that s=1/2ft^2 or s=1/2f(t)square

Expert Reply
Tue June 19, 2012

Initial speed =0

Thus using the third equation of motion we can find the final velocity after moving a distance s.


After that the car moved at a constant speed for t time we can calculate the distance travelled:


Now after that it is decelerated by f/2 so we can find the distance covered as:


Now total distance travelled is 5s



Related Questions
Fri August 11, 2017

Q.solve question 18

Mon August 07, 2017

plz ans the question

Home Work Help