Question
Thu January 27, 2011 By: Amitha N

a balloon is going up at a steddy velocity of 12m/s at a height of 32m above the ground an object is dropped from it.How long does it take for the object to reach the ground?

Expert Reply
Thu January 27, 2011
Dear student,
 
Just before hitting the gorund,
 
PE = KE
 
mgh = 1/2 m v^2
 
gh = 1/2
 
9.8 X 32 = 1/2 v^2
 
v^2 = 627.2
v = 25.04 m/s
 
S = d/t
25.04 = 32/t
t = 1.3 sec approx.
 
Hope this helps.
Thanking you
Team
Topperelarning.com
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