Question
Sun March 03, 2013 By: Sunny Acharjee

0.52 g gluoe is dissolved in 80.2 g of water, calcula the boiling point of the solution. (kb or water in 0.52kg mol^-1)

Expert Reply
Mon March 04, 2013
ΔTb = Kb x Wb x 1000  / Mb  x WA.
Given : 
 
Kb = 0.52   , WB = 0.52 g , Mb = 180g ( C6H12O6)  , 80.2 g
 
ΔTb = answer of the above.
Boiling point of the solution = Î”Tb ( the answer above) + 100 Â°( boiling point of water)
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