Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on them is noted and recorded in the following table: 

Sum 

2

3

4

5

6

7

8

9

10

11

12

Frequency

14

30

42

55

72

75

70

53

46

28

15

From the above data, what is the probability of getting a sum

(i) more than 10 (ii) between 8 and 12.

Asked by Topperlearning User 11th December 2013, 3:40 AM
Answered by Expert
Answer:

Total number of trials = 500

(i) P(sum more than 10) =

(ii) P(sum between 8 and 12) =

Answered by Expert 11th December 2013, 5:40 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp