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CBSE - IX - Physics - Alternating Current

two bulbs whose resistances are in ratio 1:2 are connected in parallel to a source of constant voltage what will be the ratio of power dissipated in the bulbs?

Asked by Harshita 24th September 2013, 7:57 AM
Answered by Expert


R1:R2 = 1:2
They are connected in parallel across source of voltage V.
Thus, the potential difference across each of them is V.
Now, the power dissipated across the resistor is P = V2/R
Thus, the ratio of power is:
Answered by Expert 24th September 2013, 9:29 AM

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