two bulbs whose resistances are in ratio 1:2 are connected in parallel to a source of constant voltage what will be the ratio of power dissipated in the bulbs?
Asked by Harshita | 24th Sep, 2013, 07:57: AM
R1:R2 = 1:2
They are connected in parallel across source of voltage V.
Thus, the potential difference across each of them is V.
Now, the power dissipated across the resistor is P = V2/R
Thus, the ratio of power is:
Answered by Romal Bhansali | 24th Sep, 2013, 09:29: AM
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