ICSE Class 10 Answered
The line x-4y=6 is the perpendicular bisector of the line AB. If B=(1,3); find the co-ordinates of A
Asked by anaghanair2204 | 05 Apr, 2019, 01:33: PM
Expert Answer
If line x-4y = 6 is perpendicular bisector of line segment AB, equation of line segment AB is of the form 4x+y = k,
where k is a constant to be determined.
since line 4x+y = k is passing through B(1,3), we have 4(1) + 3 = k = 7
Hence eqn. of line segment AB is 4x+y = 7
Point of intersection of x-4y = 6 and 4x+y = 7 is obtained by solving the equations of lines.
we get point of intersection as (2, -1) .
Since this point of intersection is midpoint of line segment AB, we get coordinate of A as (3, -5)
Answered by Thiyagarajan K | 05 Apr, 2019, 03:41: PM
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