CBSE Class 6 Answered
The difference between the C.I and S.I on Rs 8000 for 3 years is Rs 61 .find rate
Asked by rishikeshkumar15092000 | 17 Jan, 2019, 09:27: PM
Expert Answer
Simple Intrest = pnr/100 = 8000×3×r/100 = 240r
Let us calculate compound intrest every year
end of first year intrest = 8000×r/100 = 80r
end of first year Amount = (8000 + 80r)
end of second year inrest = (8000+80r)×(r/100) = 80r + (8r2/10)
end of second year Amount = 8000+160r + (8r2/10)
end of third year intrest = [ 8000+160r + (8r2/10) ]×(r/100) = 80r + (160r2 /100 ) + (8r3 /1000)
end of third year amount = 8000+240r + (240r2/100) + (8r3 /1000)
hence compound intrest after 3 years = 240r + (240r2/100) + (8r3 /1000)
difference between Simple intrest and Compound Intrest = (8r3 /1000) + (240r2/100) = 61
difference = 8r3 + 2400r2 = 61×1000 or r3 + 300r2 = 61×125 = 7625 .......(1)
put r =1 , LHS of eqn.(1) = 301 ≠ RHS
put r =2 , LHS of eqn.(1) = 1208 ≠ RHS
put r =3, LHS of eqn.(1) = 2727 ≠ RHS
put r =4 , LHS of eqn.(1) = 4864 ≠ RHS
put r =5 , LHS of eqn.(1) = 7625 = RHS
hence rate of intrest = 5%
Answered by Thiyagarajan K | 18 Jan, 2019, 05:41: PM
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