CBSE Class 8 Answered
Solve this problem? 
Asked by hemanttkumarr | 02 Dec, 2017, 10:37: PM
Expert Answer
Given :
n =4
ml =1
ms = -1/2
let's find no. of orbitals with the help of following formula,
no. of orbitals = n2 = 42 = 16
Maximum no. of electrons = 2 χ 16 = 32
But we have given ms = -1/2
therefore,
no. of electrons = 32 χ (-1/2) = 16 e-
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