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Asked by sarveshvibrantacademy | 10 May, 2019, 10:22: AM
Expert Answer
As shown in figure, when the cylinderical container is not filled with liquid,
angle of emergence θ for the top of board at the right edge of container is given by, tanθ = 2 or sinθ = 2/√5
After filling the container with liquid, bottom of the board is seen due to refraction.
If 
is angle of incidence at liquid-air boundary for the light ray going from bottom of the board,
is angle of incidence at liquid-air boundary for the light ray going from bottom of the board,then we have tan = 1 or sin = 1/√2
= 1 or sin = 1/√2refractive index of liquid μ = sinθ / sin = 2√2 / √5
= 2√2 / √5
Answered by Thiyagarajan K | 11 May, 2019, 09:40: AM
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