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Asked by adjacentcalliber10 | 05 May, 2019, 01:01: PM
Expert Answer
we have lens equation, 
.................(1)
.................(1)where v = lens-to-image distance, u = -0.4 m and f = +0.3 m
hence we get v = 1.2 m from eqn.(1)
If we differentiate eqn.(1), we get, 
................(2)
................(2)hence fron eqn.(2) , dv/dt = (1.44/0.16)×0.01 = 0.09 m/s
magnification = v/u = 1.2/(-0.4) = -3
Answered by Thiyagarajan K | 05 May, 2019, 02:01: PM
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