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CBSE Class 12-science Answered

sir this doubt please
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Asked by jyothisam9303 | 13 Oct, 2020, 05:04: PM
answered-by-expert Expert Answer
When the conducting wire loop ACB moves in a magnetic field, Induced EMF is developed between the points A and B.
 
induced EMF = v × B × l ..............(1)
 
where v is speed of moving loop, B is magnetic field induction and l is arc length.
 
since displacement x = a sin(ωt)   ,  speed v = dx/dt = a ω cos( ω t ) .................(2)
 
hence induced EMF, e(t) = [ a × ω × B × l ] cos (ωt)  .................(3)
 
Since induced EMF is alternating voltage , current through capacitor = e(t) / impedence 
 
impedence of capacitor = 1 / ( ω C )
 
Current through capacitor = [ a × ω2 × B × l × C] cos (ωt)
 
Maximum current = [ a × ω2 × B × l × C] 
Answered by Thiyagarajan K | 14 Oct, 2020, 12:19: AM
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