CBSE Class 12-science Answered
sir this doubt please
Asked by jyothisam9303 | 13 Oct, 2020, 05:04: PM
Expert Answer
When the conducting wire loop ACB moves in a magnetic field, Induced EMF is developed between the points A and B.
induced EMF = v × B × l ..............(1)
where v is speed of moving loop, B is magnetic field induction and l is arc length.
since displacement x = a sin(ωt) , speed v = dx/dt = a ω cos( ω t ) .................(2)
hence induced EMF, e(t) = [ a × ω × B × l ] cos (ωt) .................(3)
Since induced EMF is alternating voltage , current through capacitor = e(t) / impedence
impedence of capacitor = 1 / ( ω C )
Current through capacitor = [ a × ω2 × B × l × C] cos (ωt)
Maximum current = [ a × ω2 × B × l × C]
Answered by Thiyagarajan K | 14 Oct, 2020, 12:19: AM
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