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ICSE Class 10 Answered

Sir A trader bought a no. Of article for rs1200 ten were damaged and he sold each of the rest at rs2 more than what he paid for it , thus getting a profit of rs 60 on the whole transection. Taking the no. Of article he bought as x, form an equation in X and solve
Asked by nikharaayush | 06 Mar, 2019, 09:59: PM
answered-by-expert Expert Answer
Let number of articles purchased  = x
 
cost price of all the articles = Rs. 1200
 
cost price of each article = ( 1200/x )
 
since 10 articles are damaged, number of articles sold = (x - 10)
selling price of each article (1200/x ) + 2
 
selling price of all the articles sold =[ (1200/x) + 2 ](x-10)
 
profit =  [ (1200/x) + 2 ](x-10) - 1200 = Rs.60  
 
By simplifying the above expression, we get,  x2 -40x -6000 = 0 ...................(1)
 
By factorising LHS of eqn.(1), we get (x-100)(x+60) = 0   hence x = 100 is acceptable solution or number of articles purchased is 100
Answered by Thiyagarajan K | 06 Mar, 2019, 10:53: PM

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