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CBSE Class 12-science Answered

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Asked by pratib1968 | 07 Oct, 2018, 05:29: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight x with rightwards harpoon with barb upwards on top space equals space 10 straight i with hat on top plus 3 straight j with hat on top space and space straight y with rightwards harpoon with barb upwards on top space equals space 12 straight i with hat on top space minus 5 straight j with hat on top space and space stack space straight z with rightwards harpoon with barb upwards on top space equals space straight a straight i with hat on top space plus space 11 straight j with hat on top space
stack XY space with rightwards harpoon with barb upwards on top space equals space 2 straight i with hat on top space minus space 8 straight j with hat on top
YZ with rightwards harpoon with barb upwards on top space equals space open parentheses straight a minus 12 close parentheses straight i with hat on top space plus space 16 straight j with hat on top space
According space to space the space condition space for space collinearity space of space vectors
fraction numerator 2 over denominator straight a minus 12 end fraction equals fraction numerator negative 8 over denominator 16 end fraction
Solving space this space we space get space straight a space equals space 8 end style
Answered by Sneha shidid | 08 Oct, 2018, 11:54: AM
CBSE 12-science - Maths
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CBSE 12-science - Maths
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CBSE 12-science - Maths
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