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CBSE - XII Science - Mathematics - Integrals


Asked by Varsneya Srinivas 21st October 2017, 4:48 PM
Answered by Expert


begin mathsize 16px style Integration space you space can space solve space it space using space partial space fraction space as space follows colon
fraction numerator 3 straight t to the power of 4 plus 1 over denominator open parentheses straight t minus 3 close parentheses open parentheses straight t squared plus 3 close parentheses end fraction equals fraction numerator straight A over denominator straight t minus 3 end fraction plus fraction numerator Bt plus straight C over denominator straight t squared plus 3 end fraction
You space will space get space straight A space equals space 61 over 3 comma space straight B space equals space 56 over 3 comma space straight C space equals space 20
Then space solve space the space integration space using space definite space integral.
After space taking space derivative space of space the space function space solve space using space limit space straight x rightwards arrow plus infinity
end style
Answered by Expert 14th December 2017, 5:00 PM

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