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CBSE Class 11-commerce Answered

Question no. 8
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Asked by Payal | 18 Feb, 2018, 06:37: PM
answered-by-expert Expert Answer
begin mathsize 16px style limit as straight x rightwards arrow 0 of space fraction numerator ax plus straight b over denominator straight x plus 1 end fraction equals 2 fraction numerator 0 plus straight b over denominator 0 plus 1 end fraction equals 2 straight b equals 2 limit as straight x rightwards arrow infinity of space fraction numerator ax plus straight b over denominator straight x plus 1 end fraction equals 1 limit as straight x rightwards arrow infinity of space fraction numerator begin display style ax over straight x end style plus begin display style straight b over straight x end style over denominator begin display style straight x over straight x end style plus begin display style 1 over straight x end style end fraction equals 1 limit as straight x rightwards arrow infinity of space fraction numerator straight a plus straight b over straight x over denominator 1 plus 1 over straight x end fraction equals 1 straight a equals 1 rightwards double arrow straight f left parenthesis straight x right parenthesis equals fraction numerator ax plus straight b over denominator straight x plus 1 end fraction equals fraction numerator straight x plus 2 over denominator straight x plus 1 end fraction straight f left parenthesis negative 2 right parenthesis equals fraction numerator negative 2 plus 2 over denominator negative 2 plus 1 end fraction equals 0 end style
Answered by Sneha shidid | 19 Feb, 2018, 10:59: AM

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