Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
For Business Enquiry


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

Q1.prove that maximum area of right triangle inscribed in a circle is isosceles

Asked by 6th March 2009, 8:46 PM
Answered by Expert

Given a circle with radius r.

Let triangle ABC be a right triangle inscribed in the circle.

Since the triangle is a right triangle, hence one of the angle is 90o.

Let angle C = 90o

Then AB is diameter of the circle, since angle in semi circle is 90o

Hence, AB= 2r, let BC=x and AC = y

Area of traingle ABC = A = 1/2 * x*y

Applying pythagoras theorem in triangle ABC, we het

y = ((2r)2-x2) = (4r2-x2)

Putting this value of y in area

A = 1/2 * x * (4r2-x2)

Differentiating A with respect to x, we get

Answered by Expert 20th March 2009, 12:38 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp