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Prove that.....

Asked by 25th August 2008, 8:34 PM
Answered by Expert
Answer:

cos(x/2)*cos(x/4)*cos(x/8)..........=(sinx)/x

taking log on both sides, we get,

log[cos(x/2)]+log[cos(x/4)]....=log [sinx]-logx

taking derivative on both sides wrt x, we get,

-(1/2)(tan[x/2])-(1/4)tan(x/4)-...= -tanx -(1/x)

taking derivative again,

we get the result.

Answered by Expert 19th March 2009, 8:38 AM
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