CBSE Class 12-science Answered
pls explain
Asked by mufeedatvp2000 | 18 Apr, 2020, 02:22: PM
Expert Answer
x = A cos( ω t + δ ) ....................(1)
If phase angle δ = α + (π/2) , then eqn.(1) is written as,
x = A cos [ ω t + α + (π/2)] = - A sin( ω t + α ) ...................(2)
y = A cos( ω t + α ) ......................(3)
By squaring and adding of eqn.(2) and eqn.(3), we get,
x2 + y2 = A2 [ sin2( ω t + α ) + cos2( ω t + α ) ] = A2 .......................(4)
Hence from above eqn.(4), we conclude that the particle subjected to two simple harmonic motion as per eqn.(1) and eqn.(3)
will move in a circular path of radius A .
In order to get the direction of circular motion, let us plot the trajectory by considering
some values for Amplitude A, angular velocity ω , initial phase angles α and δ.
Let A = 10 cm , ω = 5 rad/s , α = (π/6) and δ = (π/6)+(π/2) = (2π/3)
Excel plot of trajectory along with table of x, y displacement values as a function of time is given below
From the tabulated values of x and y displacement and trajectory plot, we see that the particle is moving in counter clockwise direction
Answered by Thiyagarajan K | 18 Apr, 2020, 11:20: PM
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