NEET Class neet Answered
Please solve this question
Asked by brijk456 | 12 Aug, 2019, 06:40: PM
Expert Answer
We know that for a mass loaded spring executing SHM, 
...................(1)
...................(1)where ω is angular frequency, k is spring constant and m is mass attached to spring
using the relation ω = 2π/T , where T is period of oscillation, spring constant k is obtained from eqn.(1) as
k = ( 4π2× m ) / T2 ..........................(1)
when 700 g is removed, system oscillates with period 3 sec, hence k = ( 4π2× 0.9 )/9 = 0.4 π2 N/m
After removing 500 g , mass attached to spring becomes only 400 g
Hence time period 
Answered by Thiyagarajan K | 12 Aug, 2019, 08:18: PM
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