NEET Class neet Answered
Please solve this problem
Asked by Www.manashjyoti333 | 20 Nov, 2019, 12:50: AM
Expert Answer
when a hollow sphere with a small hoe is immersed in water, initially a bubble of radius equal to the hole radius
is formed as shown in figure. When the bubble breaks, then water enters into the hollow sphere.
excess pressure ΔP inside the bubble is given by, ΔP = ρgh = 4T/r ......(1)
where ρ is density of water, g is acceleration due to gravity, h is height of water column above the hole of sphere,
T is surface tension and r is hole radius
hence we get, r = 4T / ( ρgh ) = ( 4×0.07) / ( 1000 × 9.8 × 40 × 10-2 ) = 7.143 × 10-5 m
diameter of hole = 2 × 7.143 × 10-5 m = 14.286 × 10-5 m = 0.143 mm
Answered by Thiyagarajan K | 20 Nov, 2019, 12:43: PM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
