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ICSE Class 10 Answered

PLEASE solve the 4th question  
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Asked by nishabr7 | 25 Jan, 2019, 08:21: PM
answered-by-expert Expert Answer
Let x be the savings Amount invested to buy two kinds of share.
 
First share is purchased with 80% of amount, hence invested amount in first share 0.8x
 
If first share is purchased with 20% premeium, number of shares = ( 0.8x/120 )
if each share is giving 10% divident, then total divedent amount of first share = ( 0.8x/120)×10 .......................(1)
 
Invested amount in second share 0.2x
 
If second share is purchased with 20% discount, number of shares = (0.2x/40)
if each share is giving 20% divident, then total divedent amount of second share = ( 0.2x/40)×10 ..................(2)
 
Total earnings from both the share, using eqn.(1) and eqn.(2) = begin mathsize 12px style open parentheses fraction numerator begin display style 0.8 x end style over denominator begin display style 120 end style end fraction close parentheses 10 space plus space open parentheses fraction numerator 0.2 x over denominator 40 end fraction close parentheses 10 space equals space 5600 end style
begin mathsize 12px style 0.8 x space plus space 0.6 x space equals space 5600 cross times 12 space space o r space space x space equals space 48000 end style
hence total amount invested = Rs.48000
 
number of shares of first kind = (0.8×48000)/120 = 320
 
Overall return  = (5600/48000)×100 ≈ 11.67 %
Answered by Thiyagarajan K | 26 Jan, 2019, 08:33: AM

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