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If space 125 to the power of open parentheses straight n minus 1 close parentheses end exponent plus 100 equals 5 to the power of open parentheses 2 straight n minus 1 close parentheses end exponent comma space find space the space value space of space straight n.

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Asked by Topperlearning User 28th September 2016, 9:54 AM
Answered by Expert
Answer:

125 to the power of open parentheses straight n minus 1 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent
open parentheses 5 cubed close parentheses to the power of open parentheses straight n minus 1 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent
5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent
5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent minus 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent equals 120
5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent open parentheses 25 minus 1 close parentheses equals 120
5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent cross times 24 equals 120
5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent equals 120 over 24 equals 5 to the power of 1
therefore open parentheses 3 straight n minus 3 close parentheses equals 1
3 n equals 4
n equals 4 over 3

Answered by Expert 28th September 2016, 11:54 AM
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