ICSE Class 7 Answered

$If space 125 to the power of open parentheses straight n minus 1 close parentheses end exponent plus 100 equals 5 to the power of open parentheses 2 straight n minus 1 close parentheses end exponent comma space find space the space value space of space straight n.$ Please provide solution to this question

Asked by Topperlearning User | 28 Sep, 2016, 09:54: AM

Expert Answer

$125 to the power of open parentheses straight n minus 1 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent open parentheses 5 cubed close parentheses to the power of open parentheses straight n minus 1 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent plus 120 equals 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent 5 to the power of open parentheses 3 straight n minus 1 close parentheses end exponent minus 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent equals 120 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent open parentheses 25 minus 1 close parentheses equals 120 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent cross times 24 equals 120 5 to the power of open parentheses 3 straight n minus 3 close parentheses end exponent equals 120 over 24 equals 5 to the power of 1 therefore open parentheses 3 straight n minus 3 close parentheses equals 1 3 n equals 4 n equals 4 over 3$

Answered by | 28 Sep, 2016, 11:54: AM

ICSE Class 7 Answered

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