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Please give me the complete solution of 

Asked by Balbir 23rd October 2017, 8:55 PM
Answered by Expert
Answer:
begin mathsize 16px style integral straight x squared over open parentheses px plus straight q close parentheses squared dx
Put space px plus straight q equals straight t space rightwards double arrow space straight x space equals space fraction numerator straight t minus straight q over denominator straight p end fraction
pdx space equals space dt
integral fraction numerator begin display style open parentheses fraction numerator straight t minus straight q over denominator straight p end fraction close parentheses squared end style over denominator straight t squared end fraction space dt over straight p
1 over straight p cubed integral fraction numerator begin display style open parentheses straight t minus straight q close parentheses squared end style over denominator straight t squared end fraction dt
fraction numerator begin display style 1 end style over denominator begin display style straight p cubed end style end fraction integral fraction numerator straight t squared minus 2 tq plus straight q squared over denominator straight t squared end fraction dt
fraction numerator begin display style 1 end style over denominator begin display style straight p cubed end style end fraction integral open parentheses 1 minus fraction numerator 2 straight q over denominator straight t end fraction plus straight q squared over straight t squared close parentheses dt
Integrate space further space using space formuale. end style
Answered by Expert 15th December 2017, 10:55 AM
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