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Please

Asked by shettyatul17 | 02 Jun, 2019, 06:45: AM

Expert Answer

2^a = 3^b = 6^-c = k (say)

Consider, 2^a = k

log 2^a = log k

alog 2 = log k

a = log k/log 2

Similarly b = log k/log 3 and c = -log k/log 6

Put it in the ab + bc + ca and solving it further we get

ab + bc + ca = 0

Answered by Sneha shidid | 03 Jun, 2019, 09:41: AM

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