NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 08 Mar, 2020, 09:40: PM
Expert Answer
Capacitance of parallel plate capacitor without any dielectric material,
[ εo A ] /d = [ εo π r2 ] / d = C ...................(1)
where εo is permittivity of free space, A is area of parallel plates, r is radius of plate and d is separation between plates
when space between parallel plate capacitor is partially filled with dielectric of radius r/2,
capacitor is divided into two parts, one with dielectric and remaining one without dielectric.
Both capacitors are connected in parallel.
Hence capacitance after the space is partially filled with dielectric is given by
{ [ εr εo π ( r2 / 4 ) ] / d } + { [ εo π ( r2 -( r2 / 4 ) ) ] / d } = Cnew .................(2)
where εr is dielectric constant that equals 6
Hence, eqn.(2) becomes, (3/2) { [ εo π r2 ] / d } + (3/4) { [ εo π r2 ] / d } = (9/4) { [ εo π r2 ] / d } = Cnew
Using eqn.(1), we get, Cnew = (9/4) C
Answered by Thiyagarajan K | 09 Mar, 2020, 12:36: AM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
