NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 07 Dec, 2019, 10:22: PM
Expert Answer
Let the wire bent 90° be on the y and x-axis as shown in figure.
Let P be the point on z-axis at a distance 35 cm from bend point of wire.
At point P, we have magnteic flux density Bx due to wire lying on y-axis .
Similarly we have magnetic flux density By due to wire lying on x-axis.
| Bx | = | By | = μo i / (4π × 0.35 ) = (1/7) × 10-6 T
Resutant magnetic flux density = { Bx2 + By2 }1/2 = ( √2/7 )× 10-6 T ≈ 2 μT
Answered by Thiyagarajan K | 08 Dec, 2019, 04:05: PM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
