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Asked by Prashant DIGHE | 19 Jul, 2019, 05:13: PM
Expert Answer
Current in the circuit before short circuiting E2 , I1 = ( E1+E2) /( r1 + r2 +R) .....................(1)
Current in the circuit after short circuiting E2 , I2 = ( E1) /( r1 +R) .......................(2)
for I2 > I1 , we have , ( E1) /( r1 +R) > ( E1+E2) /( r1 + r2 +R) ......................(3)
from eqn.(3), we get, ( E1 r2 ) > E2 ( R + r1 )
Answered by Thiyagarajan K | 20 Jul, 2019, 10:56: AM
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