NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 26 Apr, 2020, 10:09: PM
Expert Answer
velocity vector ,
x-component of velocity , ( dx/dt ) = k1 ................(1)
If we integrate eqn.(1) by considering x = 0 at t = 0, then we get x = k1 t .................... (2)
y-component of velocity ( dy/dt ) = k2 x = k2 k1 t ...............(3)
In above equation x is substituted using eqn.(2)
By integrating eqn.(3) by considering y = 0 at t = 0, we get y = (1/2)( k2 k1 ) t2 ...................(4)
Equation (2) and (4) gives the coordinate of particle as a function of time.
Trajectory of particle is obtained from eqn. (2) and eqn.(4) by eliminating time t
let us substitute t = x / k1 using eqn.(2) and rewrite eqn.(4) as ,
y = (1/2) ( k2 k1 ) [ x/k1 ]2 = [ k2 / ( 2 k1 ) ] x2
Answered by Thiyagarajan K | 27 Apr, 2020, 08:27: AM
Application Videos
NEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT