NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 14 Mar, 2020, 10:25: PM
Expert Answer
If a capacitor of capacitance 10μF is charged with potential difference 100 V,
then charge acquired by capacitor, Q = C V = 10 μF × 100 V= 1000 μC .
Now after disconnecting battery, if 10 μF capacitor is connetce parallel to another capacitor
so that potential difference across parallel capacitors is 40 V.
Then equivalent capacitance Ceq = Q / V = 1000 μC / 40 V = 25 μF
Since the previous capacitor is 10 μF , additional capactor connected parallel is 15 μF
Answered by Thiyagarajan K | 14 Mar, 2020, 11:16: PM
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