CBSE Class 12-science Answered
Please answer the attached question
Asked by nabihamajeed | 31 Oct, 2020, 09:13: PM
Expert Answer
Maximum current im = vm / XL
where vm is peak value of alternating voltage and XL is reactance of inductor
Reactance of inductor = XL = L ω
where L is inductance and ω is angular frequency
Given inductance L = 2 H .
If we compare alternating voltage form v = vm sin(ω t) with given aletrnating voltage (200√2 ) sin(100t) ,
we get ω = 100 rad /s and vm = 200√2 Volt
Maximum current im = ( 200√2 ) / ( 2 × 100 ) A = √2 A
Ammeter will read RMS current = im / √2 = ( √2 / √2 ) A = 1 A
Answered by Thiyagarajan K | 31 Oct, 2020, 10:41: PM
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