CBSE Class 12-science Answered
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Asked by jain.pradeep | 18 Feb, 2020, 08:27: PM
Expert Answer
Initial Capacitance C = εo ( A/d )
where εo is permittivity of free space, A is area of parallel plates and d is distance between parallel plates.
if distance d between plates is doubled, capacitance C' = ( εo A) /(2d) = (1/2) ( εo A) /d = (1/2) C
Initial potential difference between plates V = Q/C
where Q is charge on plates.
Potential difference V' after changing distance d to 2d is given by, V' = Q/[ (1/2) C) = 2 V
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(i) Charge stored on capacitor remains constant after changing the distance between capacitor plates
(ii) Inital field strength Ei = V/d
Field strength after changing distance Ef = 2V / (2d) = Ei
(iii) Initial energy Ui stored in capacitor = (1/2)CV2
Energy stored in capacitor after changing the distance d between plates ,
Uf = (1/2) [ (1/2)C ] (2V)2 = C V2
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Answered by Thiyagarajan K | 19 Feb, 2020, 10:49: AM
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