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CBSE Class 12-science Answered

Maths 1
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Asked by alanpeter9611 | 14 Feb, 2019, 12:06: AM
answered-by-expert Expert Answer
Let l be length of rectangle and l/2 is its breadth.
 
Length of wire to be cut to form the above rectangle = 2 [ l + (l/2) ] = 3l
 
remaining length of wire to form square = 34 - 3l
 
side of the squire to be formed = (34 - 3l)/4
 
Area  A begin mathsize 12px style equals space l squared over 2 plus 1 over 16 open parentheses 34 minus 3 l close parentheses squared end style
Let us differentiate the relation for area and equate it to zero to get minimum area
 
hence begin mathsize 12px style fraction numerator d A over denominator d l end fraction space equals space l space minus space 3 over 8 left parenthesis 34 minus 3 l right parenthesis space equals space 0 end style .....................(1)
By solving the above eqn.(1), we get l = 6 m
 
Required length of wire to form rectangle = 18 m
Required length of wire to from square = 16 m
Answered by Thiyagarajan K | 14 Feb, 2019, 07:33: AM
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