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# Integrate sin 4x/sin 2x

Asked by 8th August 2012, 7:05 PM
Answered by Expert
Answer:
Integral (sin 4x/sin 2x) dx
Integral (2sin 2x cos 2x /sin 2x) dx            [Using the formula: sin 2x = 2 sinx cosx]
= Integral (2cos 2x) dx
= 2 * 1/2 * (sin2x) + C
= sin2x + C

Answered by Expert 8th August 2012, 9:52 PM
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