ICSE Class 8 Answered
If p²+q²+r²=58 & pq+qr+rp=21, find (p+q+r)
Asked by justjasonpong | 21 Nov, 2018, 06:37: PM
Expert Answer
(p+q+r)2 = p2 + q2 + r2 + 2( pq + qr + rp)
(p+q+r)2 = 58 + 2( 21 ) = 100
(p+q+r) = ± 10
Answered by Thiyagarajan K | 22 Nov, 2018, 01:35: AM
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