 1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

022-62211530

Mon to Sat - 11 AM to 8 PM

# hi dear

Asked by 27th May 2008, 9:54 AM

# Factor theorem

In algebra, the factor theorem is a theorem for finding out the factors of a polynomial (an expression in which the terms are only added, subtracted or multiplied, e.g. x2 + 6x + 6). It is a special case of the polynomial remainder theorem.

The factor theorem states that a polynomial f(x) has a factor xk if and only if f(k) = 0.

An example

You wish to find the factors of

x3 + 7x2 + 8x + 2.

To do this you would use trial and error finding the first factor. When the result is equal to 0, we know that we have a factor. Is (x − 1) a factor? To find out, substitute x = 1 into the polynomial above:

x3 + 7x2 + 8x + 2 = (1)3 + 7(1)2 + 8(1) + 2
= 1 + 7 + 8 + 2
= 18

As this is equal to 18—not 0—(x − 1) is not a factor of x3 + 7x2 + 8x + 2. So, we next try (x + 1) (substituting x = − 1 into the polynomial):

( − 1)3 + 7( − 1)2 + 8( − 1) + 2.

This is equal to 0. Therefore x − ( − 1), which is to say x + 1, is a factor, and -1 is a root of x3 + 7x2 + 8x + 2.

The next two roots can be found by algebraically dividing x3 + 7x2 + 8x + 2 by (x + 1) to get a quadratic, which can be solved directly, by the factor theorem or by the quadratic equation. = x2 + 6x + 2 and therefore (x + 1) and x2 + 6x + 2 are the factors of x3 + 7x2 + 8x + 2.

Answered by Expert 23rd June 2008, 2:27 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10