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find the value of x

Asked by 20th February 2009, 5:24 PM
Answered by Expert
Answer:

these two vectors are parallel.

so cross product will be zero.

(2i + 3j - k ) x ( 4i+6j +xk) = 0

12k -2xj -12k +3xi -4j +6i =0

setting coefficients of i and j and k equal to zero.

2x+4 =0  and 3x + 6 =0

==> x= -2

Answered by Expert 20th February 2009, 10:48 PM
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