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ICSE Class 10 Answered

find the equations of the line through the intersection of 2x+5y-4=0 with x axis and parallel to the line 3x-7y+8=0
Asked by ushanihar12 | 05 Feb, 2019, 10:00: PM
answered-by-expert Expert Answer
If the required line is parallel to 3x - 7y + 8 =0, then equation of required line is 3x - 7y = k  ................(1)
where k is constant.
 
Required line is passing through the intersection of 2x+5y-4 = 0 and x-axis. hence y-coordinate of intersection point is zero
 
hence x coordinate of intersection point  is obtained from 2x - 4 = 0.    or   x = 2
 
Hence line whose equation is given in (1), is passing through (2, 0).
if we substitute x=2 and y=0, then we get k value given in eqn.(1) is ,  k =6
 
Hence equation of required line is 3x - 7y = 6
Answered by Thiyagarajan K | 05 Feb, 2019, 10:37: PM

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