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CBSE Class 12-science Answered

Find the equation of the plane containing the point (1,2,3),perpendicular to the plane and parallel to the line (x-6)/3=(y-7)/2=(z-7)/-2. Write the equation in dot product form.
Asked by lekhakarthikeyan | 25 Nov, 2018, 09:17: PM
answered-by-expert Expert Answer
Wordings of the question gives ambiguity.
I assume it is required to find a plane that contains a point (1.2.3) and perpendicular a line which is parallel to the line  (x-6)/3 = (y-7)/2 = (z-7)/(-2)
 
direction ratios of the given line are  ( 3, 2, -2 )
 
The line perpendicular to the plane also has the above direction ratios because the perpendicular line  is parallel to the given line.
 
Hence the equation for plane is  begin mathsize 12px style open square brackets open parentheses x minus 1 close parentheses stack i space with hat on top space plus space left parenthesis y minus 2 right parenthesis j with overbrace on top space plus space left parenthesis z minus 3 right parenthesis k with overbrace on top close square brackets. left parenthesis 3 i with hat on top space plus space 2 j with hat on top space minus 2 k with hat on top space right parenthesis space equals space 0 end style
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