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Find the area of a triangle whose vertices are (3,0),(0,2) and (-4,0).

Asked by Topperlearning User 24th August 2017, 2:50 PM
Answered by Expert
Answer:

AC=AD+CD=3+4=7 units
Area of the ABC = ACBD==7 square units
Answered by Expert 24th August 2017, 4:50 PM
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