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CBSE Class 12-science Answered

Find second derivative of 5x      explain in great detail
Asked by haroonrashidgkp | 24 Aug, 2018, 10:55: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight f left parenthesis straight x right parenthesis space equals 5 to the power of straight x space
fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction straight f left parenthesis straight x right parenthesis equals space space straight d over dx 5 to the power of straight x space equals space 5 to the power of straight x space log space 5 space space open parentheses since comma space fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction straight a to the power of straight x space equals space straight a to the power of straight x space loga close parentheses

fraction numerator begin display style straight d squared end style over denominator begin display style dx squared end style end fraction straight f left parenthesis straight x right parenthesis equals space fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction 5 to the power of straight x space log space 5 space
space space space space space space space space space space space space equals 5 to the power of straight x space fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction log space 5 space plus space log space 5 space fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction 5 to the power of straight x space space space... open parentheses fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction straight u. straight v space equals straight u space fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction straight v space plus space straight v fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction straight u close parentheses
space space space space space space space space space space space space equals 5 to the power of straight x left parenthesis 0 right parenthesis space plus space log space 5 left parenthesis 5 to the power of straight x log space 5 right parenthesis space space space.... open parentheses fraction numerator begin display style straight d end style over denominator begin display style dx end style end fraction loga equals space 0 close parentheses
space space space space space space space space space space space space equals log squared left parenthesis 5 right parenthesis. space 5 to the power of straight x end style
Answered by Yasmeen Khan | 27 Aug, 2018, 12:45: PM
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