CBSE Class 9 Answered
Factorise : (i) (8b3 - 1)
(ii) (p3q3 + 343)
Asked by Topperlearning User | 10 Jul, 2014, 01:30: PM
Expert Answer
(i) (8b3 - 1) = [(2b)3 - 1]
= (2b - 1) [(2b)2 + 2b 
1 + 12)
= (2b - 1) (4b2 + 2b + 1)
(ii) (p3q3 + 343)
= [(pq)3 + 73]
= (pq + 7) ((pq)2 - pq7 + 72)
= (pq + 7) (p2q2 - 7pq + 49)
Answered by | 10 Jul, 2014, 03:30: PM
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