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Detailed answers please

Asked by g_archanasharma | 04 Apr, 2019, 08:41: AM

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begin mathsize 16px style straight y equals fraction numerator straight x squared over denominator 1 plus straight x squared end fraction straight y plus yx squared equals straight x squared straight y equals straight x squared left parenthesis 1 minus straight y right parenthesis straight x squared equals fraction numerator straight y over denominator 1 minus straight y end fraction straight x equals square root of fraction numerator straight y over denominator 1 minus straight y end fraction end root As space fraction numerator straight y over denominator 1 minus straight y end fraction greater or equal than 0 1 minus straight y greater than 0 Hence comma space straight y element of left square bracket 0 comma space 1 right parenthesis end style

Answered by Sneha shidid | 04 Apr, 2019, 09:33: AM

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JEE main - Maths

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JEE main - Maths

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Asked by masrulmallick014 | 25 Dec, 2023, 10:41: PM

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JEE main - Maths

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Asked by maheshv9090 | 16 Oct, 2023, 09:30: PM

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JEE main - Maths

Q) Find the range of f(x) = x + 1/x Ans) See the image which I have uploaded.. I have just broken the eqn into √x² + 1/√x² +2 -2 ..and have formed the identity (a+b)² and the range is coming (-∞, 2 ] U [ -2, ∞ ) which is wrong.. the correct range is coming from (a-b)² which is (-∞, -2 ] U [ 2, ∞ ). My Doubt- Why (a+b)² is not giving the correct range? Request- Please send the solution using (a+b)². I've attached an image and let me know if I'm wrong somewhere or why the correct solution isn't coming by using (a+b)². Thanks, Samit Future Top 50 ranker in JEE ADVANCE

Asked by samithatty | 01 Dec, 2022, 10:32: PM

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