Detailed answers please

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Detailed answers please

Asked by g_archanasharma | 01 Apr, 2019, 09:20: AM

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begin mathsize 16px style straight f left parenthesis straight x right parenthesis equals straight x minus 1 over straight x straight f left parenthesis straight x squared right parenthesis equals straight x squared minus 1 over straight x squared Consider comma space straight f left parenthesis straight x right parenthesis plus straight f left parenthesis negative straight x right parenthesis equals open parentheses straight x minus 1 over straight x close parentheses plus open parentheses negative straight x plus 1 over straight x close parentheses equals 0 straight f left parenthesis straight x right parenthesis straight f left parenthesis negative straight x right parenthesis equals open parentheses straight x minus 1 over straight x close parentheses open parentheses negative straight x plus 1 over straight x close parentheses equals negative open parentheses straight x minus 1 over straight x close parentheses squared straight f left parenthesis straight x right parenthesis minus straight f left parenthesis negative straight x right parenthesis equals straight x minus 1 over straight x minus open parentheses negative straight x plus 1 over straight x close parentheses equals 2 straight x minus 2 over straight x Hence comma space correct space option space is space straight D end style

Answered by Sneha shidid | 01 Apr, 2019, 10:01: AM

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Q) Find the range of f(x) = x + 1/x Ans) See the image which I have uploaded.. I have just broken the eqn into √x² + 1/√x² +2 -2 ..and have formed the identity (a+b)² and the range is coming (-∞, 2 ] U [ -2, ∞ ) which is wrong.. the correct range is coming from (a-b)² which is (-∞, -2 ] U [ 2, ∞ ). My Doubt- Why (a+b)² is not giving the correct range? Request- Please send the solution using (a+b)². I've attached an image and let me know if I'm wrong somewhere or why the correct solution isn't coming by using (a+b)². Thanks, Samit Future Top 50 ranker in JEE ADVANCE

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