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CBSE - IX - Mathematics - Circles

abcd is a cyclic quad. in which AE is drawn parallel to CD and BA is produced to F . if<abc=70degree  and <fae=30 degree, find <bcd.

Asked by krishan_5 3rd March 2016, 7:47 AM
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CBSE - IX - Mathematics - Circles

prove that quadrilateral formed by cyclic quad. is also cyclic.

Asked by krishan_5 3rd March 2016, 7:39 AM
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CBSE - IX - Mathematics - Circles

In a circle of BO  is  of radius=5cm, AB and AC are two chords such that AB=AC=6CM, find the length of the chord BC?
 

Asked by krishan_5 2nd March 2016, 8:33 AM
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CBSE - IX - Mathematics - Circles

PROVE THAT ANGLE BISECTOR OF ANY ANGLE OF A TRIANGLE AND PERPENDICULAR BISECTOR OF THE OPPOSITE SIDE IF INTERSECT,THEY WILL INTERSECT ON CIRCUMCIRCLE OF THE TRIANGLE.

Asked by vrishti TOKAS 22nd February 2016, 8:06 PM
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CBSE - IX - Mathematics - Circles

Plz solve the 18th question. 

Asked by ahujarajesh11 22nd January 2016, 6:09 PM
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CBSE - IX - Mathematics - Circles

PROVE THAT THE LINE OF CENTRES OF TWO INTERSECTING CIRCLES SUBTEND EQUAL ANGLES AT THE TWO PONTS OF INTERSECTION.

Asked by vrishti TOKAS 12th January 2016, 12:51 PM
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CBSE - IX - Mathematics - Circles

THE DIAGNOLS OF A CYCLIC QUADRILATERAL ARE AT RIGHT ANGLES.PROVE THAT THE PERPENDICULAR FROM THE POINT OF INTERSECTION ON ANY SIDE WHEN PRODUCED BACKWARDS,BISECTS THE OPPOSITE SIDE.

Asked by vrishti TOKAS 12th January 2016, 12:49 PM
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CBSE - IX - Mathematics - Circles

1)AB IS A DIAMETER OF A CIRCLE WITH CENTRE O.CD IS A CHORD EQUAL TO THE RADIUS OF THE CIRCLE.AC AND BD WHEN EXTENDED INTERSECT AT POINT E.PROVE THAT ANGLE AEB=60 DEGREE.(HINT-JOIN OC,OD AND BC)

Asked by vrishti TOKAS 12th January 2016, 12:47 PM
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CBSE - IX - Mathematics - Circles

explain the rules of circle [ex-sss,sas]

Asked by taranarora200 14th March 2015, 9:20 PM
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CBSE - IX - Mathematics - Circles

in a triangle ABC angle A is 60 and the altitudes from. B and C meet AC and AB at P and Q and intersect each other at I prove that APIQ and PQBC are cyclic quadrilaters

Asked by chaturvedi.pragya2000 13th March 2015, 1:54 PM
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